24=9x^2=28x

Solution for 24=9x^2=28x equation:

24=9x^2=28x

We move all terms to the left:

24-(9x^2)=0

a = -9; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-9)·24
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*-9}=\frac{0-12\sqrt{6}}{-18}
=-\frac{12\sqrt{6}}{-18}
=-\frac{2\sqrt{6}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*-9}=\frac{0+12\sqrt{6}}{-18}
=\frac{12\sqrt{6}}{-18}
=\frac{2\sqrt{6}}{-3}
$